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In ∆ABC, D and E are points on sides AB and AC, respectively, such that DE || BC and AD : DB = 3: 1. If EA = 3.3 cm, then find the value of AC.
Question

In ∆ABC, D and E are points on sides AB and AC, respectively, such that DE || BC and AD : DB = 3: 1. If EA = 3.3 cm, then find the value of AC.

A.

4 cm

B.

1.1 cm

C.

5.5 cm

D.

4.4 cm

Correct option is D

Given:
In ΔABC , D and E are points on sides AB and AC respectively such that DE∥BC.
The ratio AD : DB = 3 : 1.
EA = 3.3cm.
Concept Used:
Since DE∥BC, by the Basic Proportionality Theorem (Thales' Theorem), the ratio of the segments on the sides of the triangle will be the same:
ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}​​
Solution:
By Thales theorem:
AEEC=ADDB 3.3EC=31  EC=1.1 cm\frac{AE}{EC}=\frac{AD}{DB}\\ \ \\\frac{3.3}{\text{EC}} = \frac{3}{1} \\ \ \\\implies \text{EC} = 1.1 \, cm​​
Now, AC = AE + EC = 3.3 + 1.1 = 4.4 cm
Thus, The length of AC is 4.4 cm.

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