In a triangle ∆ABC, the ∠ABC = 90°. If sin(A) = $$\frac{1}{2}$$​, then cos(C) is equal to:

Correct option is D

Concept Used:

Sum of all angles in triangle is $$180\degree$$ 

​Solution:

So, ∠ABC = 90° and sin(A) = $$\frac12$$ 

​sin(A) = $$\frac12$$ 

sin A = sin 30$$\degree$$

A = 30$$\degree$$ 

In Triangle ABC, the sum of all angles be 180$$\degree$$ 

So, $$\angle$$C = $$180\degree - [\angle A+\angle B]= 180\degree -[30+ 90]= 60\degree$$ 

So, cosC = cos$$60\degree = \frac 12$$​​