In a given reaction, which element acts as an ion?

​$$Pb(s) + CuCl_2(g) \rightarrow PbCl_2(aq) + Cu(s)$$​​

Correct option is D

• Pb (Lead) is in its solid state (Pb(s)) and reacts with CuCl₂ (Copper chloride). Lead (Pb) loses electrons and forms Pb²⁺ ions, which then combine with chloride (Cl⁻) ions to form PbCl₂ in aqueous form.
• Cu in CuCl₂ exists as Cu²⁺ ions. The copper ion gains electrons and is reduced to solid copper (Cu).
• Cl comes from the CuCl₂ (Copper chloride), and as part of the salt, it exists as Cl⁻ ions in the solution, which are part of the ionic compound PbCl₂.