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    In the reaction: 2H₂ + O₂ → 2H₂O, if 5 moles of H₂ and 2 moles of O₂ are mixed, the limiting reagent is:
    Question

    In the reaction: 2H₂ + O₂ → 2H₂O, if 5 moles of H₂ and 2 moles of O₂ are mixed, the limiting reagent is:

    A.

    H₂

    B.

    H₂O

    C.

    CO₂

    D.

    O₂

    Correct option is D

    The correct answer is: (d) O₂

    Explanation:

    • Balanced equation: 2H₂ + 1O₂ → 2H₂O

    • From the equation, 2 moles of H₂ react with 1 mole of O₂.

    • Given:

      • H₂ = 5 moles

      • O₂ = 2 moles

    To fully react with 5 moles of H₂, we would need:
    → (1 mol O₂ / 2 mol H₂) × 5 mol H₂ = 2.5 moles of O₂

    But only 2 moles of O₂ are available.
    Hence, O₂ is the limiting reagent (it will be used up first and limit the amount of product formed).

    Information Booster:

    • Limiting reagent determines the maximum amount of product that can be formed.

    • Excess reagent remains unreacted.

    • Identifying the limiting reagent is crucial in yield calculations.

    • This concept is essential in stoichiometry and industrial chemical processes.

    • After the limiting reagent is consumed, the reaction stops.

    • Theoretical yield is based only on the amount of the limiting reagent.

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