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In the reaction: 2H₂ + O₂ → 2H₂O, if 5 moles of H₂ and 2 moles of O₂ are mixed, the limiting reagent is:
Question

In the reaction: 2H₂ + O₂ → 2H₂O, if 5 moles of H₂ and 2 moles of O₂ are mixed, the limiting reagent is:

A.

H₂

B.

H₂O

C.

CO₂

D.

O₂

Correct option is D

The correct answer is: (d) O₂

Explanation:

  • Balanced equation: 2H₂ + 1O₂ → 2H₂O

  • From the equation, 2 moles of H₂ react with 1 mole of O₂.

  • Given:

    • H₂ = 5 moles

    • O₂ = 2 moles

To fully react with 5 moles of H₂, we would need:
→ (1 mol O₂ / 2 mol H₂) × 5 mol H₂ = 2.5 moles of O₂

But only 2 moles of O₂ are available.
Hence, O₂ is the limiting reagent (it will be used up first and limit the amount of product formed).

Information Booster:

  • Limiting reagent determines the maximum amount of product that can be formed.

  • Excess reagent remains unreacted.

  • Identifying the limiting reagent is crucial in yield calculations.

  • This concept is essential in stoichiometry and industrial chemical processes.

  • After the limiting reagent is consumed, the reaction stops.

  • Theoretical yield is based only on the amount of the limiting reagent.

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