​

In a frog species, foot webbing is controlled by a single gene where the allele for nonwebbed feet (W) is dominant and webbed feet (w) is recessive. Assume there is a population of 500 individuals, where:

• 320 have the genotype WW
• 160 have the heterozygous genotype Ww
• 20 have the genotype ww

What are the frequencies of the three genotypes and alleles in this population?

Correct option is C

Hence option 3 is correct

Information Booster:

1. Hardy-Weinberg Principle:

   • The sum of allele frequencies must be 1, i.e., $p+q=1$.
   • The sum of genotype frequencies must also be 1, i.e., p2+2pq+q2=1p^2 + 2pq + q^2 = 1p2+2pq+q2=1.

2. Genotype Frequencies Formula:

   • Homozygous dominant (WW) = p2p^2p2
   • Heterozygous (Ww) = $2pq$
   • Homozygous recessive (ww) = q2q^2q2

3. Allele Frequency Calculation:

   • The dominant allele (W) frequency is found by adding all WW individuals and half of Ww individuals.
   • The recessive allele (w) frequency is found by adding all ww individuals and half of Ww individuals.