In a ∆ABC, the internal bisectors of the angle B and the angle C intersect at an angle of 105°. What is the value of the angle A?

In a ∆ABC,

Internal bisectors of  $$\angle$$​ B and $$\angle$$​ C intersect and make an angle 105° 

Concept Used: ​

In a ∆ABC, 

if the internal bisector of $$\angle$$B and $$\angle C$$ intersect at point O.

Then, $$\angle BOC = 90^0 + \frac { \angle A}{2}$$ 

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