In a ∆ABC, if 2∠A = 3∠B = 6∠C, then find the value of ∠C.

Correct option is B

Given:
In triangle ∆ABC, it is given that 2∠A = 3∠B = 6∠C.
Formula Used:
Sum of angles in a triangle: ∠A + ∠B + ∠C = 180°
Solution:
Let 2∠A = 3∠B = 6∠C = x
Then, ∠A = $$\frac x2$$​, ∠B = $$\frac x3$$​, ∠C = $$\frac x6$$​​
​$$\frac{x}{2} + \frac{x}{3} + \frac{x}{6} = 180$$​​
​$$\Rightarrow \frac{3x + 2x + x}{6} = 180 \\\Rightarrow \frac{6x}{6} = 180 \\\Rightarrow x = 180 \\\text{Now, } \angle C = \frac{x}{6} = \frac{180}{6} = 30^\circ$$​​