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In a 2 km linear race, if P completes the race in 200 second and Q in 220 seconds, then the distance by which P beats Q is:
Question

In a 2 km linear race, if P completes the race in 200 second and Q in 220 seconds, then the distance by which P beats Q is:

A.

167611 \frac{6}{11}​ metres

B.

173711 \frac7{11}​ metres

C.

191711 \frac7{11}​ metres

D.

181911\frac 9{11}​ metres

Correct option is D

Given:
Total time taken by P to complete race = 200 seconds
Total time taken by Q to complete race = 220 seconds
Distance=2 km
Formula Used:
Speed = DistanceTime\frac{\text{Distance}}{\text{Time}}​​

Solution:
Speed of Q = 2000220=10011 m/sec\frac{2000}{220} = \frac{100}{11} \, \text{m/sec}​​
When P finishes race Q is left 20 seconds behind,
Then distance left will be distance travelled by Q in 20 seconds
Distance = 10011 m/sec×20=200011 m=181 911 m\frac{100}{11} \, \text{m/sec} \times 20 = \frac{2000}{11} \, \text{m} = 181 \, \frac{9}{11} \, \text{m}​​

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