In a race, an athlete covers a distance of 456 m in 152 sec in the first lap. He covers the second lap of the same length in 76 sec. What is the average speed (in m/sec) of the athlete?

Correct option is A

Given:

Distance of one lap = 456 m

Time for first lap = 152 sec

Time for second lap = 76 sec

Formula Used:
Average Speed = $$\frac{\text{Total Distance }}{\text{ Total Time}}$$​​

Solution:

Total distance = 456 + 456 = 912 m

Total time = 152 + 76 = 228 sec

Average Speed =$$\frac{912}{228}$$​= 4 m/sec