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If xy=32\frac{x}{y} = \frac{3}{2}yx​=23​​, then find (x2+y2)(x2−y2).​\frac{(x² + y²)} { (x² - y²)}.​(x2−y2)(x2+y2)​.​​​
Question

If xy=32\frac{x}{y} = \frac{3}{2}​, then find (x2+y2)(x2y2).\frac{(x² + y²)} { (x² - y²)}.​​​

A.

95\frac{9}{5}​​

B.

115\frac{11}{5}​​

C.

135\frac{13}5​​

D.

75\frac{7}5​​

Correct option is C

Given: 
xy=32\frac{x}{y} = \frac{3}{2} 
To find: (x2+y2)(x2y2).\frac{(x² + y²)} { (x² - y²)}.​ 
Solution:
Let x = 3k  and y = 2k 
Now, substituting the values in the expression;
=(3k)2+(2k)2(3k)2(2k)2 =9k2+4k29k24k2 =13k25k2 =135=\frac{(3k)^2 + (2k)^2}{(3k)^2 - (2k)^2} \\ \ \\ = \frac{9k^2 + 4k^2}{9k^2 - 4k^2} \\ \ \\ = \frac{13 \cancel {k^2}}{5\cancel{k^2}} \\ \ \\ =\bf \frac{13}{5}​​​​

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