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Find the square root of a2b2+b2a2+2\frac{a^2}{b^2}+\frac{b^2}{a^2}+2b2a2​+a2b2​+2 ​
Question

Find the square root of a2b2+b2a2+2\frac{a^2}{b^2}+\frac{b^2}{a^2}+2 ​

A.

ab2\frac{a -b}{2}​​

B.

ab+ba\frac{a}{b}+\frac{b}{a}​​

C.

abba\frac{a}{b} - \frac{b}{a}​​

D.

a2bb2a\frac{a}{2b} -\frac{b}{2a}​​

Correct option is B

Given: 
To find: square root of  a2b2+b2a2+2\frac{a^2}{b^2} + \frac{b^2}{a^2}+2 
Formula Used: 
(a+b)2=a2+b2+2ab(a+b)^2 = a^2 +b^2 +2ab  
Solution: 
a2b2+b2a2+2 =a4+b4+2a2b2a2b2 =(a2+b2)2a2b2 =a2+b2ab or, =ab+ba\sqrt{\frac{a^2}{b^2} + \frac{b^2}{a^2}+2} \\ \ \\ = \sqrt{\frac{a^4 +b^4 + 2 a^2b^2}{a^2b^2}} \\ \ \\ = \sqrt{\frac{(a^2 + b^2)^2}{a^2b^2}} \\ \ \\ = \frac{a^2+b^2}{ab}\\ \ \\ \textbf{or} ,\\ \ \\ =\frac{a}{b} +\frac{b}{a} 

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