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If O be the centre of the incircle of a triangle ABC and ∠BOC = 110°, then the value of ∠BAC will be- 
Question

If O be the centre of the incircle of a triangle ABC and ∠BOC = 110°, then the value of ∠BAC will be- 

A.

40°

B.

55°

C.

110°

D.

20°

Correct option is A

Given:
∠BOC = 110°
O is the incenter of triangle ABC.
Formula used:
∠BOC = 90° + (A/2), where A = ∠BAC
Solution:
110° = 90° + (A/2)
A/2 = 20°
A = 40°
Correct answer is (a) 40°

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