If $$x^3-9x^2+26x-24=0$$​, then which of the values of x given in the options will provide an INCORRECT solution to the given equation?

Correct option is D

Given:

The cubic equation is:

​$$x^3 - 9x^2 + 26x - 24 = 0$$​

Solution:

​$$x^3 - 9x^2 + 26x - 24 = 0.$$​​

Option A: x = 3

Substitute x = 3 into the equation:

​$$(3)^3 - 9(3)^2 + 26(3) - 24 = 27 - 81 + 78 - 24 = 0$$​

So, x = 3 is a solution.

Option B: x = 4

Substitute x = 4 into the equation:

​$$(4)^3 - 9(4)^2 + 26(4) - 24 = 64 - 144 + 104 - 24 = 0$$​

So, x = 4 is a solution.

Option C: x = 2

Substitute x = 2 into the equation:

​$$(2)^3 - 9(2)^2 + 26(2) - 24 = 8 - 36 + 52 - 24 = 0$$​

So, x = 2 is a solution.

Option D: x = 1

Substitute x = 1 into the equation:

​$$(1)^3 - 9(1)^2 + 26(1) - 24 = 1 - 9 + 26 - 24 = -6$$​

Since $$-6 \neq 0,$$ x = 1 is NOT a solution.