Factorise the polynomial $$x^4 - 10x^2 + 22$$​ into product of two quadratic polynomials.

Correct option is D

Given:
​$$x^4 - 10x^2 + 22.$$ 
Formula Used:
​$$\text{Roots of equation} = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ 
Solution:
Let y = x^2
Given Polynomial becomes $$y^2 - 10y + 22.$$​​
$$\text{Roots of equation} = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$​
where a = 1, b = -10, and c = 22.

Therefore, the two roots of the quadratic are:
y = 5 + √3 and y = 5 - √3
Now, substitute y = x^2 back into the factored form:
(x^2 - (5 + √3))(x^2 - (5 - √3))
The factorisation of x^4 - 10x^2 + 22 is: (x^2 - (5 + √3))(x^2 - (5 - √3))