Correct option is A
Given:
x2−1 is a factor of ax4+bx3+cx2+dx+e
Solution:
Substitute x = 1 and x = -1 in the polynomial:
f(1)=a(1)4+b(1)3+c(1)2+d(1)+e=a+b+c+d+e=0
f(−1)=a(−1)4+b(−1)3+c(−1)2+d(−1)+e=a−b+c−d+e=0
a + b + c + d + e = 0
a - b + c - d + e = 0
Adding the two equations:
2a + 2c + 2e = 0=>a+c+e = 0
Subtracting the second from the first:
2b + 2d = 0=>b + d = 0
a + c + e = b + d