If $$x+y+z=0$$​, then the value of $$\frac{x^2}{yz}+\frac{y^2}{zx}+\frac{z^2}{xy}$$​ is:

Correct option is C

​Given:

x + y + z = 0

Concept Used:

$$x^3 + y^3 + z^3$$= 3xyz when x + y + z = 0

​​Solution:

Let’s denote the expression as:

S = $$\frac{x^2}{yz} + \frac{y^2}{zx} + \frac{z^2}{xy}$$​

S =$$\frac{x^3 + y^3 + z^3}{xyz}$$​

So,

S = $$\frac{3xyz}{xyz} = 3$$​