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    If x : y = 7 : 3, then (x2+y2x^2+y^2x2+y2​ ) : (x2−y2x^2-y^2 x2−y2) = ?
    Question

    If x : y = 7 : 3, then (x2+y2x^2+y^2​ ) : (x2y2x^2-y^2 ) = ?

    A.

    29 : 20

    B.

    25 : 4

    C.

    5 : 2

    D.

    5 : 1

    Correct option is A

    Given:

    x : y = 7 : 3

    Concept Used:
    For ratios, x : y = a : b .

    Solution:  
    Let,  x = 7k  and y = 3k 

    x2+y2x2y2 =(7k)2+(3k)2(7k)2(3k)2 =49k2+9k249k29k2 =58k240k2 =2920\frac{x^2 + y^2}{x^2 - y^2} \\ \ \\ = \frac{(7k)^2 + (3k)^2}{(7k)^2 - (3k)^2} \\ \ \\= \frac{49k^2 + 9k^2}{49k^2 - 9k^2} \\ \ \\ = \frac{58k^2}{40k^2} \\ \ \\ = \frac{29}{20}​​

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