A bag contains 50 Paisa, 25 Paisa and 10 Paisa coins in the ratio 16 : 8 : 20, amounting to ₹384. Find the number of 10 Paisa coins.​

Correct option is C

Given:

The ratio of the number of 50 Paisa, 25 Paisa, and 10 Paisa coins is 16 : 8 : 20

The total amount is ₹384, which is equivalent to 384 × 100 = 38,400 Paisa

Solution:

50 × (16x) + 25 × (8x) + 10 × (20x) = 38400

800x + 200x + 200x = 38400

1200x = 38400

x = $$\frac{38400}{1200} = 32$$​

Number of 10 Paisa coins = 20 × 32 = 640 

Alternate Method: 

16x = 50 paise

8x = 25 paise 

20x = 10 paise 

8x + 2x + 2x = 12x 

12x = 384 

x = 32 

Number of 10 Paisa coins = 20 × 32 = 640