If $$x-y=1$$​, then the value of $$x^3-y^3-3xy$$​ will be:

Correct option is C

Given:

x - y = 1

Formula Used:

Algebraic identity: (x - y)³ = x³ - y³ - 3xy(x - y)

Solution:

(x - y)³ = 1³

x³ - 3x²y + 3xy² - y³ = 1

x³ - y³ - 3xy(x - y) = 1

x³ - y³ - 3xy(1) = 1

x³ - y³ - 3xy = 1

Therefore, the value of x³ - y³ - 3xy is 1.