If $$x+\frac{1}{x}=5$$ , Then the value of $$\frac{3x}{2x^2+2-5x}$$  will be:

Correct option is B

Given: ​

​$$x+\frac{1}{x}=5$$ 

To find: $$\frac{3x}{2x^2+2-5x}$$ 

Solution: 

$$\frac{3x}{2x^2+2-5x} \\ \ \\ = \frac{3x}{x\left(2x+\frac2x-5\right)} \\ \ \\ = \frac{3}{2\left(x+\frac1x\right) -5}$$ 

Now, putting the value;

$$=\frac{3}{2\times 5-5} \\ \ \\ = \frac{3}{10 -5} = \frac{3}{5}$$​