If x + $$\frac{1}{x} = 2,$$ then the value of x² + $$\frac{1}{x²}$$ = ?​

Correct option is D

​Given:

$$x + \frac{1}{x} = 2$$​

Formula Used:

$$x^2 + \frac{1}{x^2} = \left(x + \frac{1}{x}\right)^2 - 2$$​

Solution:

Substitute $$x + \frac{1}{x} = 2$$​  into the formula:

​$$x^2 + \frac{1}{x^2} = (2)^2 - 2 = 2$$​​