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If where θ is an acute angle, then the value of sin (θ+30°) is:
Question

If where θ is an acute angle, then the value of sin (θ+30°) is:

A.


B.


C.


D.


Correct option is D

Given:  
cos2θ=32\cos^2 \theta = \frac{{3}}{2}   
sin(θ+300)\sin (\theta+30^0)  = ? 
Concept Used: 
Trigonometric table in use;
θ030456090sin(θ)01222321cos(θ)13222120tan(θ)01313undefinedcsc(θ)undefined22231sec(θ)12322undefinedcot(θ)undefined31130\begin{array}{|c|c|c|c|c|c|}\hline\theta & 0^\circ & 30^\circ & 45^\circ & 60^\circ & 90^\circ \\\hline\sin(\theta) & 0 & \frac{1}{2} & \frac{\sqrt{2}}{2} & \frac{\sqrt{3}}{2} & 1 \\\hline\cos(\theta) & 1 & \frac{\sqrt{3}}{2} & \frac{\sqrt{2}}{2} & \frac{1}{2} & 0 \\\hline\tan(\theta) & 0 & \frac{1}{\sqrt{3}} & 1 & \sqrt{3} & \text{undefined} \\\hline\csc(\theta) & \text{undefined} & 2 & \sqrt{2} & \frac{2}{\sqrt{3}} & 1 \\\hline\sec(\theta) & 1 & \frac{2}{\sqrt{3}} & \sqrt{2} & 2 & \text{undefined} \\\hline\cot(\theta) & \text{undefined} & \sqrt{3} & 1 & \frac{1}{\sqrt{3}} & 0 \\\hline\end{array} ​​
Solution: 

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