If the speeds of a train in 10 successive hours are $$a_1, a_2, a_3, a_4, a_5, a_6, a_7, a_8, a_9, \,and \, a_{10}$$​, then the average speed of the train is:

Correct option is C

Given:
Speeds of a train in 10 successive hours =$$a_1, a_2, a_3, a_4, a_5, a_6, a_7, a_8, a_9, \,and \, a_{10}$$​
Formula Used:
$$\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}$$​​
Solution:
Distance = Speed ×Time
​$$\begin{align*}d_1 & = a_1 \times 1 = a_1 \\d_2 & = a_2 \times 1 = a_2 \\d_3 & = a_3 \times 1 = a_3 \\d_4 & = a_4 \times 1 = a_4 \\d_5 & = a_5 \times 1 = a_5 \\d_6 & = a_6 \times 1 = a_6 \\d_7 & = a_7 \times 1 = a_7 \\d_8 & = a_8 \times 1 = a_8 \\d_9 & = a_9 \times 1 = a_9 \\d_{10} & = a_{10} \times 1 = a_{10}\end{align*}$$​​
=> Average speed  $$= \frac{a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + a_7 + a_8 + a_9 + a_{10}}{10}$$​​
=> So, it is clear that the average speed of the train is the arithmetic mean of $$a_1, a_2, a_3, a_4, a_5, a_6, a_7, a_8, a_9, \,and \, a_{10}$$​​