If the radius of a circle is reduced by 25%, its area is reduced by:

Correct option is D

Given:
Percentage reduced in radius of circle = 25%
Formula Used:
Area of circle = $$πr^2$$​​
where r → radius of the circle
Solution:
The radius of the circle is r.
If the radius of a circle is reduced by 25%
New radius = r - r × 0.25 = 0.75r
Old Area = $$πr^2$$​​
New Area =$$π × (0.75r)^2 = π × 0.5625r^2 = 0.5625πr^2$$​​
Percentage reduced in the area of the circle= $$\frac{πr^2 - 0.5625πr^2}{ πr^2} \times100$$ =43.75 %
Alternate Solution:

Percentage decrease = 25 + 25 - $$\frac{25 × 25}{100}$$​ = 43.75%