The price of fuel decreases by 15%, 25% and 35% in three successive months, but increases by 40% in the fourth month. What is the percentage increase/decrease in the price of fuel in the fourth month as compared to its original price?

Correct option is A

Given:

The price of fuel decreases by 15%, 25%, and 35% in three successive months.

The price increases by 40% in the fourth month.

We need to find the percentage change in the price of fuel in the fourth month compared to its original price.

Formula Used:

Percentage change = $$\left( \frac{\text{Final price}}{\text{Original price}} - 1 \right) \times 100$$​​

Solution:  ​

Let the initial Price be 100 

Final price = $$100 \times (1 - \frac{15}{100}) \times (1 - \frac{25}{100}) \times (1 - \frac{35}{100}) \times (1 + \frac{40}{100})$$

​$$=100 \times (\frac{85}{100}) \times ( \frac{75}{100}) \times ( \frac{65}{100}) \times ( \frac{140}{100}) \\ \ \\ = 58.02$$​

Percentage change = $$\left( \frac{58.02}{100}-1\right)\times100 =-41.98\%$$​​

Thus, the overall percentage change in the price of fuel after the four months is a decrease of 41.98% compared to its original price.