Correct option is B
Given:
Mode = 160
Modal class = 155 – 160
Frequencies:
f1 = 31 (modal class)
f0= 18 (preceding class)
f2 = x (succeeding class)
Class width h = 5
Formula Used:
For grouped data, the mode formula:
Mode = L + (2f1−f0−f2f1−f0)⋅h
Solution:
Lower boundary of modal class = 155
Using the formula;
160=155+(2(31)−18−x31−18)⋅5
160=155+(62−18−x13)⋅5
160−155=44−x65
5=44−x65
5(44 - x) = 65
220 - 5x = 65
155 = 5x
x = 5155 = 31