​If the distance between two points ($$x$$,7) and (1,15) is 10 units, then the possible values of $$x$$​ = ?​

Correct option is A

Given:

Distance between two points ($$x$$​​,7) and (1,15) is 10 units

Formula Used: 

AB=$$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$​​

Solution:

10= $$\sqrt{(1-x)^2+(15-7)^2}$$ 

We do both side squire 

10²= (1-x)² + (8)²​

100 = 1+x²-2x+64

x²- 2x - 35 = 0,            ​  

x^2​-7x+5x-35 = 0 

x(x-7) +5(x-7) = 0 

(x-7)(x+5) = 0

x=7, x=-5  

Option (a)