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If the average of m numbers is n and the average of n numbers is m, the average of these (m + n) numbers will be:
Question

If the average of m numbers is n and the average of n numbers is m, the average of these (m + n) numbers will be:

A.

48

B.

2mnm+n\frac{2mn}{m+n}​​

C.

mn

D.

480

Correct option is B

Given:
- Average of m numbers = n
- Average of n numbers = m
We are asked to find the average of these (m + n) numbers.
Formula Used:
- Average = (Sum of observations)(Number of observations)\frac{ (Sum \ of \ observations) }{ (Number \ of \ observations)}
- Sum = Average × Number of observations
Solution:
Find the total sum of the m numbers:
Sum₁ = m × n

Find the total sum of the n numbers:
Sum₂ = n × m
Total sum of (m + n) numbers = Sum₁ + Sum₂ = mn + mn = 2mn
Total number of observations = m + n
Average = Total sumTotal number\frac{Total \ sum }{ Total \ number}
2mn(m+n)\frac{2mn }{ (m + n)}
Hence, the average of these (m + n) numbers is: 

2mn(m+n)\frac{2mn }{ (m + n)}​​


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