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If tan⁡A=815\frac{8}{15}158​​ then find sinA+cosA.
Question

If tan⁡A=815\frac{8}{15}​ then find sinA+cosA.

A.

15/11

B.

7/17

C.

23/17

D.

8/11

Correct option is C

Given:

We are given that:
tanA=815\tan A = \frac{8}{15}​​
We need to find the value of sin A + cos A .

Solution

Step 1: Using the Pythagorean identity to find sin A and cos A :
Given tan A=815A = \frac{8}{15}​ , we can think of this as a right triangle where the opposite side is 8 and the adjacent side is 15.
Using the Pythagorean theorem, we find the hypotenuse h :

h=82+152=64+225=289=17h = \sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17​​

Now, we can find sin A and cos A :

sinA=oppositehypotenuse=817cosA=adjacenthypotenuse=1517sin A = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{8}{17}\\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{15}{17}​​

Then the value of sin A + cos A :

sinA+cosA=817+1517=8+1517=2317\sin A + \cos A = \frac{8}{17} + \frac{15}{17} = \frac{8 + 15}{17} = \frac{23}{17}​​

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