If sin⁡θ=$$\frac{7}{25}$$​, then cos⁡θ and tan⁡θ are respectively _____________.
(Where θ is in the first quadrant)

Correct option is D

Given:
sin⁡θ=7/25
Formula Used:
Pythagoras’ Theorem
​$$(H)^2 = (P)^2 + (B)^2$$​​
Where H,P,B are hypotenuse, perpendicular and base respectively of a triangle
Solution:
We know that sine of theta is the ratio of perpendicular to hypotenuse
sin⁡θ =P/H=7/25
Using Pythagoras Theorem
​$$(H)^2 = (P)^2 + (B)^2 \\\ \\(25)^2 = (7)^2 + (B)^2 \\\ \\(B)^2 = (25)^2 - (7)^2$$​​
B= 24cm
Using Pythagoras triplets

Now,
 $$cos⁡θ =\frac{B}{H} =\frac{24}{25}\\\ \\tan⁡θ =\frac{P}{B}=\frac{7}{24}$$​​