If  $$\frac{\sin^2θ - 3\sinθ + 2}{\cos^2θ} = 1$$, then what is the value of θ?

Correct option is C

Given:
​$$\frac{\sin^2θ - 3\sinθ + 2}{\cos^2θ} = 1$$​​
Formula Used:
​$$\cos^2θ = 1 - \sin^2θ$$​​
Solution:
​$$\sin^2θ - 3\sinθ + 2 = \cos^2θ$$​​
​$$\sin^2θ - 3sinθ + 2 = 1 - \sin^2θ$$​​
​$$2\sin^2θ - 3\sinθ + 1 = 0$$​​
​$$2\sin^2θ - 2\sinθ - \sinθ + 1 = 0$$​​
​$$2\sinθ(\sinθ - 1) - 1(\sinθ - 1) = 0$$​​
​$$(2\sinθ - 1)(\sinθ - 1) = 0$$​​
$$\sinθ = \frac{1}{2}$$​ or $$\sinθ = 1$$​​
If $$\sinθ = 1, \cosθ = 0$$​, which makes the denominator zero (invalid).
So, $$\sinθ = \frac{1}{2}$$​​
θ = 30°
Final Answer
So the correct answer is (c)