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If  sin⁡θ=35\sin \theta = \frac{3}{5}sinθ=53​​, where 0∘<θ<90∘0^\circ < \theta < 90^\circ0∘<θ<90∘​, find the value of  cos
Question

If  sinθ=35\sin \theta = \frac{3}{5}​, where 0<θ<900^\circ < \theta < 90^\circ​, find the value of  cosθ\cos \theta ​.

A.

45​\frac{4}{5}​​​

B.

35​\frac{3}{5}​​​

C.

34​\frac{3}{4}​​​

D.

916​\frac{9}{16}​

Correct option is A

If sin θ=35,where0<θ<90,\theta = \frac{3}{5}, where 0^\circ < \theta < 90^\circ,​ find the value of cosθ\cos \theta​.

Solution

1. Given

sinθ=OppositeHypotenuse\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}}

From sinθ=35\sin \theta = \frac{3}{5}​:

Opposite=3,Hypotenuse\text{Opposite} = 3, \quad \text{Hypotenuse}​ = 5

2. Using the Pythagorean Theorem:

Hypotenuse2=Opposite2+Adjacent2\text{Hypotenuse}^2 = \text{Opposite}^2 + \text{Adjacent}^2

Substitute values:

52=32+Adjacent25^2 = 3^2 + \text{Adjacent}^2

25=9+Adjacent225 = 9 + \text{Adjacent}^2

Adjacent2=16=>Adjacent=4\text{Adjacent}^2 = 16 \quad \Rightarrow \quad \text{Adjacent} = 4

3. Find cosθ\cos \theta​:

cosθ=AdjacentHypotenuse\cos \theta = \frac{\text{Adjacent}}{\text{Hypotenuse}}

Substitute values:

cosθ=45\cos \theta = \frac{4}{5}

Final Answer

cosθ=45\cos \theta = \frac{4}{5}

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