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    If Sin θ = 3/5, then find the value of tan 2θ
    Question

    If Sin θ = 3/5, then find the value of tan 2θ

    A.

    24/25

    B.

    12/13

    C.

    24/7

    D.

    7/24

    Correct option is C

    Given:
    sin θ = 3/5
    This forms a right triangle where:
    Opposite side = 3
    Hypotenuse = 5
    Formula:
    tan2θ=2tanθ1tan2θ\tan 2\theta = \frac{2 \tan \theta}{1 - \tan^2 \theta} ​​

    Solution:

    Use Pythagoras to find adjacent side:
    adjacent = √(5² − 3²) = √(25 − 9) = √16 = 4

    So, cos θ = 4/5, and tan θ = sin θ / cos θ = (3/5) / (4/5) = 3/4

    tan θ = 3/4

    Now,
    tan 2θ =2341(34)2=3/27/16=4814=247= \frac{2 \cdot \frac{3}{4}}{1 - \left(\frac{3}{4}\right)^2} = \frac{3/2}{7/16} = \frac{48}{14} = \frac{24}{7}​​

    Final Answer:
    (C) 24/7

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