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If sec A + tan A = 3, then cos A is equal to:
Question

If sec A + tan A = 3, then cos A is equal to:

A.

4/3

B.

3/5

C.

3/4

D.

. 5/3

Correct option is B

Given: 
secA+tanA=3\sec A+\tan A =3  
Formula Used: 
sec2A=1+tan2Asec2Atan2A=1(secAtanA)(secA+tanA)=1\sec^2A= 1 + \tan^2 A \\ \sec^2A-\tan^2A =1 \\ (\sec A-\tan A)(\sec A+\tan A) = 1  
secA=1cosA\sec A = \frac{1}{\cos A} ​
Solution:

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