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If Pcos α = 3 and 4tan α = Q, then what is the relation between P and Q, which is independent of α ?
Question

If Pcos α = 3 and 4tan α = Q, then what is the relation between P and Q, which is independent of α ?

A.

9P2+16Q2=1 \frac{9}{P^2} + \frac{16}{Q^2} = 1​​

B.

9P216Q2=1 \frac{9}{P^2} - \frac{16}{Q^2} = 1​​

C.

P29Q216=1 \frac{P^2}{9} - \frac{Q^2}{16} = 1​​

D.

P29+Q216=1 \frac{P^2}{9} + \frac{Q^2}{16} = 1​​

Correct option is C

Given:

Pcos α = 3

4tan α = Q

Formula Used:

We use the following trigonometric identities:

sin²α + cos²α = 1

tan α = sin α / cos α

Solution:

Pcosα=3 cosα=3P secα=P34tanα=Q tanα=Q4From the given concept, we getsec2αtan2α=1 P29Q216=1P \cos \alpha = 3 \\\implies \cos \alpha = \frac{3}{P} \\\implies \sec \alpha = \frac{P}{3} \\4 \tan \alpha = Q \\\implies \tan \alpha = \frac{Q}{4} \\\text{From the given concept, we get} \\\sec^2 \alpha - \tan^2 \alpha = 1 \\\implies \frac{P^2}{9} - \frac{Q^2}{16} = 1​​​

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