If n resistors with $$R\Omega$$​ each as resistance are connected in parallel, then the equivalent resistance of the network is:

Correct option is A

The correct answer is  (A)$$\frac{R}{n} \,Ω$$​

Explanation:

Whennnresistors, each with resistance$$RΩ$$​, are connected in parallel, the formula for the equivalent resistance$$R_{\text{eq}}$$​ is given by:

​$$1Req=1R+1R+⋯(n terms) = \frac{n}{R}$$​​

Thus, the equivalent resistance becomes:

​$$Req= \frac{R}{n}$$​​

So, the equivalent resistance ofnnresistors connected in parallel is 

Information Booster:

• The formula for parallel resistors is derived from the inverse sum of individual resistances.

• Fornnresistors of resistanceR, the total resistance reduces with the increase in the number of resistors.

• The equivalent resistance decreases as more resistors are added in parallel.

• This is useful in circuits requiring a lower resistance for current flow.

• Parallel resistances always result in a value lower than any individual resistance.

• The relationship is reciprocal, meaning as the number of resistors increases, the equivalent resistance approaches zero.