If θ is an acute angle and tanθ = $$\frac{48}{55}$$​, then what is the value of cosecθ?

Correct option is A

Given:

$$\tan \theta = \frac{48}{55}$$​​

θ is an acute angle

Formula Used:
In a right-angled triangle,

​$$\tan \theta = \frac{\text{Perpendicular }}{\text{Base}},$$​​

​$$\cosec \theta = \frac{\text{Hypotenuse}}{\text{Perpendicular}}$$​​

Solution:
Given: $$\tan \theta = \frac{48}{55}$$​, so

Perpendicular = 48, Base = 55

Hypotenuse =$$\sqrt{48^2 + 55^2} = \sqrt{2304 + 3025} = \sqrt{5329} = 73$$​​

So, $$\cosec \theta = \frac{73}{48}$$​