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    If cot4x+cot2x=1cot^4x + cot^2x = 1cot4x+cot2x=1​, then the value of cosec4x−cosec2xcosec^4x - cosec^2xcosec4x−cosec2x is:
    Question

    If cot4x+cot2x=1cot^4x + cot^2x = 1​, then the value of cosec4xcosec2xcosec^4x - cosec^2x is:

    A.

    1

    B.

    2

    C.

    4

    D.

    -1

    Correct option is A

    Given: 

    cot4x+cot2x=1 \cot^4 x + \cot^2 x = 1​​

    Concept Used; 

    cosec2x=1+cot2x\cosec^2 x = 1 + \cot^2 x 

    cosec2x - 1 = cot2x  

    (a -b)2​ = a2+ b2-2ab

    Solution: 

    cot4x+cot2x=1 \cot^4 x + \cot^2 x = 1 

    (cot2x)cot2x+cot2x=1 (cosec2x1)2+cosec2x1=1 cosec4x+12cosec2x+cosec2x1=1 cosec4xcosec2x+11=1 cosec4xcosec2x=1(\cot^2x)\cot^2x + \cot^2x = 1 \\ \ \\ (\cosec^2x-1)^2+ \cosec^2x - 1 = 1 \\ \ \\ \cosec^4x + 1 -2\cosec^2x + \cosec^2x -1 = 1\\ \ \\ \cosec^4x - \cosec^2x +1-1 = 1\\ \ \\ \cosec^4x - \cosec^2x = 1

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