Correct option is B
Given:
m = cotA + cosA
n = cotA − cosA
Formula Used:
Solution:
Add m and n:
m + n = cotA + cosA + (cotA − cosA)
m + n = 2cotA
Subtract m and n:
m - n = cotA + cosA - (cotA − cosA)
m − n = 2cosA
Square difference: