If  $$\cot\frac{\text{π}}{2}-\text{θ})=\frac{1}{\sqrt3}$$​, then find the value of cos $$\text{θ}$$​.

Correct option is B

Given: ​

​$$\cot(\frac{\text{π}}{2}-\text{θ})=\frac{1}{\sqrt3}$$ 

To find ; cos$$\text{θ}$$ 

Formula Used: ​

​$$\cot(\frac{\text{π}}{2}-\text{θ})= \tan \theta$$  

​$$\tan30\degree = \frac1{\sqrt3} \\ \ \\ \cos 30\degree = \frac{\sqrt3}{2}$$ 

Solution: ​

​$$\cot(\frac{\text{π}}{2}-\text{θ})=\frac{1}{\sqrt3} \\ \ \\ \tan \theta = \frac{1}{\sqrt3} \\ \ \\ \tan \theta = \tan 30\degree \\ \ \\ \theta = 30\degree$$ 

Now, 

​$$\cos 30\degree = \frac{\sqrt3}{2}$$​​

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