If △ABC is right angled at B,AB=12cm and ∠CAB=60^∘, determine the length of BC.

Given: ​

△ABC is right angle triangle,

AB = 12cm and ∠CAB = $$60^0$$ 

Formula Used:  

For right angle triangle,

​$$\tan \theta = \frac{ \text{Perpendicular}}{\text{Base}}$$ 

$$\tan 30^0 = \frac{1}{\sqrt{3}}$$ 

$$\tan 60^0 =\sqrt{3}$$