If $$\text{a}^3-\text{b}^3=602$$​ and a - b = 2, then find the value of ($$\text{a}^2+\text{b}^2$$​).

Correct option is A

Given:

​$$a^3 - b^3 = 602, \quad a - b = 2$$

Formula Used:

a² + b² = (a - b)² + 2ab

(a - b)³= a³ - b³ - 3ab (a - b)

Solution: 

Substitute the value in Formulas:

a² + b² = 4 + 2ab ..........(i)

(2)³ =  602 - 3 ab $$\times 2$$

8 = 602 - 6ab

6ab = 594

ab = $$\frac{594}{6}$$ 

ab = 99 .........(ii)

Putting the value of (ii) equation in the (i) equation:

a² + b² = 4 + 2 $$\times$$ 99

​a² + b² = 4 + 198

a² + b²  = 202

Thus, the correct option is (a) 202