If A's salary is 16% more than that of B, then by what percentage is B's salary less than that of A (correct to two decimal places)?​

Correct option is A

Given:
Salary of A is 16% more than salary of B.
Solution:
Let the salary of B be 100x.
Salary of A = 100x + 100x × 16% = 116x
​$$\text{Percentage Difference} = \left( \frac{116x - 100x}{116x} \right) \times 100\\\Rightarrow \left( \frac{16x}{116x} \right) \times 100\\\Rightarrow 13.79\%\\$$​​
∴ B's salary is 13.79% less than that of A