If A’s income is 70% more than B’s income, then what percentage less does B earn than A?

Correct option is B

Given:

A’s income is 70% more than B

Formula Used:

Percentage Decrease= $$\frac{Decrease\ in\ Value}{Original\ Value} \times 100$$​​

Solution:

Let B’s income be 100

Then A’s income will be 100 + 70% of 100 =170

B earn less than A = 170 -100 = 70

Percentage =$$\frac{70}{170} \times 100 =\frac{700}{17}= 41\frac{3}{17}\%$$​​