If a cot⁡θ=b, then the value of $$\frac{(a cos⁡θ-b sin⁡θ )}{(a cos⁡θ+b sin⁡θ )}$$​= ?  

Correct option is C

Given:

​$$\\a \cot \theta = b$$​​

Solution:

$$\frac{(a cos⁡θ-b sin⁡θ )}{(a cos⁡θ+b sin⁡θ )}$$  

Dividing the whole equation by   $$\sin \theta,$$

Then 

​$$\frac{(a cot⁡θ-b )}{(a cot⁡θ+b )}$$    

​$$\frac{(a\times\frac{b}{a}-b )}{(a\times\frac{b}{a} +b )}$$ 

=  0 

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