If a+b=25 and a-b=13, find the value of (a+b)^2.

Correct option is A

Given:

a+b=25 and a-b=13

Formula Used:

​$$(a+b)^2= a^2+b^2+2ab$$

Solution:

​$$a+b=25$$ (Equation 1)

$$a-b=13$$ (Equation 2)

Adding the equation 1 and 2

​$$a+b+a-b=38$$

$$a=19$$ 

Put in the value of $$a$$ in equation 1 the value of $$b=6$$

​​$$(a+b)^2= a^2+b^2+2ab$$ = $$(19)^2+(6)^2+2\times19\times6$$ = 625

Thus the correct answer is (A)