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    If A and B are events with P(A) = 3/8, P(B) = 1/2 and P(A∩B) = 1/4. Find P(A‾∩B‾)P(\overline{A} \cap \overline{B})P(A∩B)​
    Question

    If A and B are events with P(A) = 3/8, P(B) = 1/2 and P(A∩B) = 1/4. Find P(AB)P(\overline{A} \cap \overline{B})

    A.

    1/8

    B.

    3/8

    C.

    5/8

    D.

    7/8

    Correct option is B

    Given:
    P(A) = 3/8, P(B) = 1/2, P(A ∩ B) = 1/4
    Formula Used:
    We can use the complement rule for this probability problem. The complement of an event A is the event that A does not occur.
    The formula to find P(AB)P(\overline{A} \cap \overline{B})​is given by the complement of the union of A and B:
    P(AB)=1P(AB)P(\overline{A} \cap \overline{B}) = 1 - P(A \cup B)​​
    Also, P(A ∪ B) can be found using the formula:
    P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
    Solution:
    P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
    P(A ∪ B) = 3/8 + 1/2 – 1/4
    P(A ∪ B) = 3/8 + 4/8 - 2/8 = 5/8
    P(AB)P(\overline{A} \cap \overline{B})​ = 1 - P(A ∪ B)
    P(AB)P(\overline{A} \cap \overline{B})​= 1 - 5/8 = 3/8
    Therefore, P(AB)P(\overline{A} \cap \overline{B})​ is 3/8.

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