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If A and B are acute angles such that tan A = cot B , then the value of A + B is:
Question

If A and B are acute angles such that tan A = cot B , then the value of A + B is:

A.

90°

B.

20°

C.

60°

D.

180°

Correct option is A

Given:

tanA=cotB\tan A = \cot B​​

A and B are acute angles.

Formula Used:

Relationship between tangent and cotangent:

cotB=1tanB\cot B = \frac{1}{\tan B}​​

For acute angles, if tanA=1tanB,    thenA+B=90.\tan A = \frac{1}{\tan B},\ \ \ \ then \quad A + B = 90^\circ.​​

Solution:

tanA=1tanB\tan A = \frac{1}{\tan B}​​,  implies that A and B are complementary angles. So,

A+B=90 A + B = 90^\circ​​

Thus, The value of A + B is 90°.

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