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If a=9, b= -5 and c= -4, then find the value of a3+b3+c3a^3+b^3+c^3a3+b3+c3​​
Question

If a=9, b= -5 and c= -4, then find the value of a3+b3+c3a^3+b^3+c^3​​

A.

570

B.

560

C.

550

D.

540

Correct option is D

Given: 

a = 9, b = -5 and c = -4, 

a3+b3+c3a^3+b^3+c^3 = ?​

Solution:

a3=93=729a^3 = 9^3 = 729 

b3=(5)3=125b^3 = (-5)^3 = -125 

c3=(4)3=64c^3 = (-4)^3 = -64

Now, summing these values:

a3+b3+c3=729+(125)+(64)a^3 + b^3 + c^3 = 729 + (-125) + (-64)

a3+b3+c3=72912564a^3 + b^3 + c^3 = 729 - 125 - 64 

a3+b3+c3=729189=540a^3 + b^3 + c^3 = 729 - 189 = 540 

Thus, the value of a3+b3+c3=540a^3 + b^3 + c^3 = 540 .​

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