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    If a=9, b= -5 and c= -4, then find the value of a3+b3+c3a^3+b^3+c^3a3+b3+c3​​
    Question

    If a=9, b= -5 and c= -4, then find the value of a3+b3+c3a^3+b^3+c^3​​

    A.

    570

    B.

    560

    C.

    550

    D.

    540

    Correct option is D

    Given: 

    a = 9, b = -5 and c = -4, 

    a3+b3+c3a^3+b^3+c^3 = ?​

    Solution:

    a3=93=729a^3 = 9^3 = 729 

    b3=(5)3=125b^3 = (-5)^3 = -125 

    c3=(4)3=64c^3 = (-4)^3 = -64

    Now, summing these values:

    a3+b3+c3=729+(125)+(64)a^3 + b^3 + c^3 = 729 + (-125) + (-64)

    a3+b3+c3=72912564a^3 + b^3 + c^3 = 729 - 125 - 64 

    a3+b3+c3=729189=540a^3 + b^3 + c^3 = 729 - 189 = 540 

    Thus, the value of a3+b3+c3=540a^3 + b^3 + c^3 = 540 .​

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