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If a 1768 m long train crosses a pole in 68 seconds, then find the time (in seconds) taken by the train to cross a 338 m long platform.
Question

If a 1768 m long train crosses a pole in 68 seconds, then find the time (in seconds) taken by the train to cross a 338 m long platform.

A.

81

B.

82

C.

76

D.

77

Correct option is A

Given
Length of the train = 1768 m
Time taken to cross a pole = 68 seconds
Length of the platform = 338 m
Formula Used
Speed = DistanceTime \frac{\text{Distance}}{\text{Time}}​​
Time to cross a platform = Length of Train+Length of PlatformSpeed\frac{\text{Length of Train} + \text{Length of Platform}}{\text{Speed}}​​
Solution
Speed of the train = 176868=26\frac{1768}{68} = 26​ m/s
Total distance to cross the platform = 1768 + 338 = 2106 m
Time taken to cross the platform =210626=81 \frac{2106}{26} = 81​ seconds
Final Answer
So the correct answer is (a)

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